3.9.48 \(\int \frac {\tan ^4(c+d x)}{(a+a \sin (c+d x))^4} \, dx\) [848]

3.9.48.1 Optimal result
3.9.48.2 Mathematica [A] (verified)
3.9.48.3 Rubi [A] (verified)
3.9.48.4 Maple [A] (verified)
3.9.48.5 Fricas [A] (verification not implemented)
3.9.48.6 Sympy [F(-1)]
3.9.48.7 Maxima [B] (verification not implemented)
3.9.48.8 Giac [A] (verification not implemented)
3.9.48.9 Mupad [B] (verification not implemented)

3.9.48.1 Optimal result

Integrand size = 21, antiderivative size = 145 \[ \int \frac {\tan ^4(c+d x)}{(a+a \sin (c+d x))^4} \, dx=\frac {4 \sec ^5(c+d x)}{5 a^4 d}-\frac {16 \sec ^7(c+d x)}{7 a^4 d}+\frac {20 \sec ^9(c+d x)}{9 a^4 d}-\frac {8 \sec ^{11}(c+d x)}{11 a^4 d}+\frac {\tan ^5(c+d x)}{5 a^4 d}+\frac {9 \tan ^7(c+d x)}{7 a^4 d}+\frac {16 \tan ^9(c+d x)}{9 a^4 d}+\frac {8 \tan ^{11}(c+d x)}{11 a^4 d} \]

output
4/5*sec(d*x+c)^5/a^4/d-16/7*sec(d*x+c)^7/a^4/d+20/9*sec(d*x+c)^9/a^4/d-8/1 
1*sec(d*x+c)^11/a^4/d+1/5*tan(d*x+c)^5/a^4/d+9/7*tan(d*x+c)^7/a^4/d+16/9*t 
an(d*x+c)^9/a^4/d+8/11*tan(d*x+c)^11/a^4/d
 
3.9.48.2 Mathematica [A] (verified)

Time = 0.80 (sec) , antiderivative size = 166, normalized size of antiderivative = 1.14 \[ \int \frac {\tan ^4(c+d x)}{(a+a \sin (c+d x))^4} \, dx=\frac {\sec ^3(c+d x) (168960-78903 \cos (c+d x)-183040 \cos (2 (c+d x))+8767 \cos (3 (c+d x))+62464 \cos (4 (c+d x))+19925 \cos (5 (c+d x))-15616 \cos (6 (c+d x))-797 \cos (7 (c+d x))+501600 \sin (c+d x)-70136 \sin (2 (c+d x))-200288 \sin (3 (c+d x))-25504 \sin (4 (c+d x))+48800 \sin (5 (c+d x))+6376 \sin (6 (c+d x))-1952 \sin (7 (c+d x)))}{3548160 a^4 d (1+\sin (c+d x))^4} \]

input
Integrate[Tan[c + d*x]^4/(a + a*Sin[c + d*x])^4,x]
 
output
(Sec[c + d*x]^3*(168960 - 78903*Cos[c + d*x] - 183040*Cos[2*(c + d*x)] + 8 
767*Cos[3*(c + d*x)] + 62464*Cos[4*(c + d*x)] + 19925*Cos[5*(c + d*x)] - 1 
5616*Cos[6*(c + d*x)] - 797*Cos[7*(c + d*x)] + 501600*Sin[c + d*x] - 70136 
*Sin[2*(c + d*x)] - 200288*Sin[3*(c + d*x)] - 25504*Sin[4*(c + d*x)] + 488 
00*Sin[5*(c + d*x)] + 6376*Sin[6*(c + d*x)] - 1952*Sin[7*(c + d*x)]))/(354 
8160*a^4*d*(1 + Sin[c + d*x])^4)
 
3.9.48.3 Rubi [A] (verified)

Time = 0.49 (sec) , antiderivative size = 149, normalized size of antiderivative = 1.03, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {3042, 3190, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\tan ^4(c+d x)}{(a \sin (c+d x)+a)^4} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {\tan (c+d x)^4}{(a \sin (c+d x)+a)^4}dx\)

\(\Big \downarrow \) 3190

\(\displaystyle \frac {\int \left (a^4 \tan ^4(c+d x) \sec ^8(c+d x)-4 a^4 \tan ^5(c+d x) \sec ^7(c+d x)+6 a^4 \tan ^6(c+d x) \sec ^6(c+d x)-4 a^4 \tan ^7(c+d x) \sec ^5(c+d x)+a^4 \tan ^8(c+d x) \sec ^4(c+d x)\right )dx}{a^8}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {\frac {8 a^4 \tan ^{11}(c+d x)}{11 d}+\frac {16 a^4 \tan ^9(c+d x)}{9 d}+\frac {9 a^4 \tan ^7(c+d x)}{7 d}+\frac {a^4 \tan ^5(c+d x)}{5 d}-\frac {8 a^4 \sec ^{11}(c+d x)}{11 d}+\frac {20 a^4 \sec ^9(c+d x)}{9 d}-\frac {16 a^4 \sec ^7(c+d x)}{7 d}+\frac {4 a^4 \sec ^5(c+d x)}{5 d}}{a^8}\)

input
Int[Tan[c + d*x]^4/(a + a*Sin[c + d*x])^4,x]
 
output
((4*a^4*Sec[c + d*x]^5)/(5*d) - (16*a^4*Sec[c + d*x]^7)/(7*d) + (20*a^4*Se 
c[c + d*x]^9)/(9*d) - (8*a^4*Sec[c + d*x]^11)/(11*d) + (a^4*Tan[c + d*x]^5 
)/(5*d) + (9*a^4*Tan[c + d*x]^7)/(7*d) + (16*a^4*Tan[c + d*x]^9)/(9*d) + ( 
8*a^4*Tan[c + d*x]^11)/(11*d))/a^8
 

3.9.48.3.1 Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3190
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((g_.)*tan[(e_.) + (f_.)*(x 
_)])^(p_.), x_Symbol] :> Simp[a^(2*m)   Int[ExpandIntegrand[(g*Tan[e + f*x] 
)^p/Sec[e + f*x]^m, (a*Sec[e + f*x] - b*Tan[e + f*x])^(-m), x], x], x] /; F 
reeQ[{a, b, e, f, g, p}, x] && EqQ[a^2 - b^2, 0] && ILtQ[m, 0]
 
3.9.48.4 Maple [A] (verified)

Time = 1.48 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.05

method result size
parallelrisch \(\frac {-\frac {64}{3465}-\frac {704 \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{105}-\frac {2048 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3465}+\frac {64 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{315}-\frac {1504 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{315}-\frac {320 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{693}-\frac {512 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{3465}-\frac {128 \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15}-\frac {32 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}-\frac {320 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{21}}{d \,a^{4} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{3} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{11}}\) \(152\)
risch \(\frac {4 i \left (5544 i {\mathrm e}^{9 i \left (d x +c \right )}+3465 \,{\mathrm e}^{10 i \left (d x +c \right )}-5280 i {\mathrm e}^{7 i \left (d x +c \right )}-10857 \,{\mathrm e}^{8 i \left (d x +c \right )}+176 i {\mathrm e}^{5 i \left (d x +c \right )}+4818 \,{\mathrm e}^{6 i \left (d x +c \right )}-1952 i {\mathrm e}^{3 i \left (d x +c \right )}-2794 \,{\mathrm e}^{4 i \left (d x +c \right )}+488 i {\mathrm e}^{i \left (d x +c \right )}+1525 \,{\mathrm e}^{2 i \left (d x +c \right )}-61\right )}{3465 \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )^{11} \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )^{3} d \,a^{4}}\) \(155\)
derivativedivides \(\frac {-\frac {1}{48 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{3}}-\frac {1}{32 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{2}}-\frac {16}{11 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{11}}+\frac {8}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{10}}-\frac {176}{9 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{9}}+\frac {28}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{8}}-\frac {179}{7 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{7}}+\frac {89}{6 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{6}}-\frac {49}{10 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}+\frac {1}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{4}}+\frac {7}{48 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}+\frac {1}{32 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}}{d \,a^{4}}\) \(190\)
default \(\frac {-\frac {1}{48 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{3}}-\frac {1}{32 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{2}}-\frac {16}{11 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{11}}+\frac {8}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{10}}-\frac {176}{9 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{9}}+\frac {28}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{8}}-\frac {179}{7 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{7}}+\frac {89}{6 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{6}}-\frac {49}{10 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}+\frac {1}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{4}}+\frac {7}{48 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}+\frac {1}{32 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}}{d \,a^{4}}\) \(190\)
norman \(\frac {-\frac {320 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{21 d a}-\frac {64}{3465 a d}-\frac {32 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5 d a}-\frac {704 \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{105 d a}-\frac {128 \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d a}-\frac {1504 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{315 d a}-\frac {512 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{3465 d a}-\frac {320 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{693 d a}-\frac {2048 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3465 d a}+\frac {64 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{315 d a}}{a^{3} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{3} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{11}}\) \(209\)

input
int(sec(d*x+c)^4*sin(d*x+c)^4/(a+a*sin(d*x+c))^4,x,method=_RETURNVERBOSE)
 
output
32/3465*(-2-726*tan(1/2*d*x+1/2*c)^6-64*tan(1/2*d*x+1/2*c)^3+22*tan(1/2*d* 
x+1/2*c)^4-517*tan(1/2*d*x+1/2*c)^5-50*tan(1/2*d*x+1/2*c)^2-16*tan(1/2*d*x 
+1/2*c)-924*tan(1/2*d*x+1/2*c)^8-693*tan(1/2*d*x+1/2*c)^9-1650*tan(1/2*d*x 
+1/2*c)^7)/d/a^4/(tan(1/2*d*x+1/2*c)-1)^3/(tan(1/2*d*x+1/2*c)+1)^11
 
3.9.48.5 Fricas [A] (verification not implemented)

Time = 0.30 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.06 \[ \int \frac {\tan ^4(c+d x)}{(a+a \sin (c+d x))^4} \, dx=-\frac {488 \, \cos \left (d x + c\right )^{6} - 1220 \, \cos \left (d x + c\right )^{4} + 1120 \, \cos \left (d x + c\right )^{2} + {\left (122 \, \cos \left (d x + c\right )^{6} - 915 \, \cos \left (d x + c\right )^{4} + 1400 \, \cos \left (d x + c\right )^{2} - 735\right )} \sin \left (d x + c\right ) - 420}{3465 \, {\left (a^{4} d \cos \left (d x + c\right )^{7} - 8 \, a^{4} d \cos \left (d x + c\right )^{5} + 8 \, a^{4} d \cos \left (d x + c\right )^{3} - 4 \, {\left (a^{4} d \cos \left (d x + c\right )^{5} - 2 \, a^{4} d \cos \left (d x + c\right )^{3}\right )} \sin \left (d x + c\right )\right )}} \]

input
integrate(sec(d*x+c)^4*sin(d*x+c)^4/(a+a*sin(d*x+c))^4,x, algorithm="frica 
s")
 
output
-1/3465*(488*cos(d*x + c)^6 - 1220*cos(d*x + c)^4 + 1120*cos(d*x + c)^2 + 
(122*cos(d*x + c)^6 - 915*cos(d*x + c)^4 + 1400*cos(d*x + c)^2 - 735)*sin( 
d*x + c) - 420)/(a^4*d*cos(d*x + c)^7 - 8*a^4*d*cos(d*x + c)^5 + 8*a^4*d*c 
os(d*x + c)^3 - 4*(a^4*d*cos(d*x + c)^5 - 2*a^4*d*cos(d*x + c)^3)*sin(d*x 
+ c))
 
3.9.48.6 Sympy [F(-1)]

Timed out. \[ \int \frac {\tan ^4(c+d x)}{(a+a \sin (c+d x))^4} \, dx=\text {Timed out} \]

input
integrate(sec(d*x+c)**4*sin(d*x+c)**4/(a+a*sin(d*x+c))**4,x)
 
output
Timed out
 
3.9.48.7 Maxima [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 488 vs. \(2 (129) = 258\).

Time = 0.23 (sec) , antiderivative size = 488, normalized size of antiderivative = 3.37 \[ \int \frac {\tan ^4(c+d x)}{(a+a \sin (c+d x))^4} \, dx=\frac {32 \, {\left (\frac {16 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {50 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {64 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} - \frac {22 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac {517 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + \frac {726 \, \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac {1650 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} + \frac {924 \, \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}} + \frac {693 \, \sin \left (d x + c\right )^{9}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{9}} + 2\right )}}{3465 \, {\left (a^{4} + \frac {8 \, a^{4} \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {25 \, a^{4} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {32 \, a^{4} \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} - \frac {11 \, a^{4} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac {88 \, a^{4} \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} - \frac {99 \, a^{4} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac {99 \, a^{4} \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}} + \frac {88 \, a^{4} \sin \left (d x + c\right )^{9}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{9}} + \frac {11 \, a^{4} \sin \left (d x + c\right )^{10}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{10}} - \frac {32 \, a^{4} \sin \left (d x + c\right )^{11}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{11}} - \frac {25 \, a^{4} \sin \left (d x + c\right )^{12}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{12}} - \frac {8 \, a^{4} \sin \left (d x + c\right )^{13}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{13}} - \frac {a^{4} \sin \left (d x + c\right )^{14}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{14}}\right )} d} \]

input
integrate(sec(d*x+c)^4*sin(d*x+c)^4/(a+a*sin(d*x+c))^4,x, algorithm="maxim 
a")
 
output
32/3465*(16*sin(d*x + c)/(cos(d*x + c) + 1) + 50*sin(d*x + c)^2/(cos(d*x + 
 c) + 1)^2 + 64*sin(d*x + c)^3/(cos(d*x + c) + 1)^3 - 22*sin(d*x + c)^4/(c 
os(d*x + c) + 1)^4 + 517*sin(d*x + c)^5/(cos(d*x + c) + 1)^5 + 726*sin(d*x 
 + c)^6/(cos(d*x + c) + 1)^6 + 1650*sin(d*x + c)^7/(cos(d*x + c) + 1)^7 + 
924*sin(d*x + c)^8/(cos(d*x + c) + 1)^8 + 693*sin(d*x + c)^9/(cos(d*x + c) 
 + 1)^9 + 2)/((a^4 + 8*a^4*sin(d*x + c)/(cos(d*x + c) + 1) + 25*a^4*sin(d* 
x + c)^2/(cos(d*x + c) + 1)^2 + 32*a^4*sin(d*x + c)^3/(cos(d*x + c) + 1)^3 
 - 11*a^4*sin(d*x + c)^4/(cos(d*x + c) + 1)^4 - 88*a^4*sin(d*x + c)^5/(cos 
(d*x + c) + 1)^5 - 99*a^4*sin(d*x + c)^6/(cos(d*x + c) + 1)^6 + 99*a^4*sin 
(d*x + c)^8/(cos(d*x + c) + 1)^8 + 88*a^4*sin(d*x + c)^9/(cos(d*x + c) + 1 
)^9 + 11*a^4*sin(d*x + c)^10/(cos(d*x + c) + 1)^10 - 32*a^4*sin(d*x + c)^1 
1/(cos(d*x + c) + 1)^11 - 25*a^4*sin(d*x + c)^12/(cos(d*x + c) + 1)^12 - 8 
*a^4*sin(d*x + c)^13/(cos(d*x + c) + 1)^13 - a^4*sin(d*x + c)^14/(cos(d*x 
+ c) + 1)^14)*d)
 
3.9.48.8 Giac [A] (verification not implemented)

Time = 0.73 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.19 \[ \int \frac {\tan ^4(c+d x)}{(a+a \sin (c+d x))^4} \, dx=-\frac {\frac {1155 \, {\left (3 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right )}}{a^{4} {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right )}^{3}} - \frac {3465 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 47355 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} + 309540 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 588588 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 891198 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 747450 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 481140 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 172700 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 35233 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 3203}{a^{4} {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}^{11}}}{110880 \, d} \]

input
integrate(sec(d*x+c)^4*sin(d*x+c)^4/(a+a*sin(d*x+c))^4,x, algorithm="giac" 
)
 
output
-1/110880*(1155*(3*tan(1/2*d*x + 1/2*c) - 1)/(a^4*(tan(1/2*d*x + 1/2*c) - 
1)^3) - (3465*tan(1/2*d*x + 1/2*c)^9 + 47355*tan(1/2*d*x + 1/2*c)^8 + 3095 
40*tan(1/2*d*x + 1/2*c)^7 + 588588*tan(1/2*d*x + 1/2*c)^6 + 891198*tan(1/2 
*d*x + 1/2*c)^5 + 747450*tan(1/2*d*x + 1/2*c)^4 + 481140*tan(1/2*d*x + 1/2 
*c)^3 + 172700*tan(1/2*d*x + 1/2*c)^2 + 35233*tan(1/2*d*x + 1/2*c) + 3203) 
/(a^4*(tan(1/2*d*x + 1/2*c) + 1)^11))/d
 
3.9.48.9 Mupad [B] (verification not implemented)

Time = 18.46 (sec) , antiderivative size = 279, normalized size of antiderivative = 1.92 \[ \int \frac {\tan ^4(c+d x)}{(a+a \sin (c+d x))^4} \, dx=\frac {\frac {64\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}}{3465}+\frac {512\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{3465}+\frac {320\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{693}+\frac {2048\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{3465}-\frac {64\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{315}+\frac {1504\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{315}+\frac {704\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6}{105}+\frac {320\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{21}+\frac {128\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8}{15}+\frac {32\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9}{5}}{a^4\,d\,{\left (\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )-\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}^3\,{\left (\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )+\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}^{11}} \]

input
int(sin(c + d*x)^4/(cos(c + d*x)^4*(a + a*sin(c + d*x))^4),x)
 
output
((64*cos(c/2 + (d*x)/2)^14)/3465 + (512*cos(c/2 + (d*x)/2)^13*sin(c/2 + (d 
*x)/2))/3465 + (32*cos(c/2 + (d*x)/2)^5*sin(c/2 + (d*x)/2)^9)/5 + (128*cos 
(c/2 + (d*x)/2)^6*sin(c/2 + (d*x)/2)^8)/15 + (320*cos(c/2 + (d*x)/2)^7*sin 
(c/2 + (d*x)/2)^7)/21 + (704*cos(c/2 + (d*x)/2)^8*sin(c/2 + (d*x)/2)^6)/10 
5 + (1504*cos(c/2 + (d*x)/2)^9*sin(c/2 + (d*x)/2)^5)/315 - (64*cos(c/2 + ( 
d*x)/2)^10*sin(c/2 + (d*x)/2)^4)/315 + (2048*cos(c/2 + (d*x)/2)^11*sin(c/2 
 + (d*x)/2)^3)/3465 + (320*cos(c/2 + (d*x)/2)^12*sin(c/2 + (d*x)/2)^2)/693 
)/(a^4*d*(cos(c/2 + (d*x)/2) - sin(c/2 + (d*x)/2))^3*(cos(c/2 + (d*x)/2) + 
 sin(c/2 + (d*x)/2))^11)